The total volume of water in Tank B, Tank C and Tank D was 236 mℓ. Ian poured out half the volume of water from Tank B, tripled the amount of water in Tank C and poured out 138 mℓ of water from Tank D. The ratio of the volume of water in Tank B to Tank C to Tank D is now 1 : 6 : 10. Find the total volume of water in the three tanks now.
| |
B |
C |
D |
| Before |
2 u |
2 u |
10 u + 138 |
| Change |
- 1 u |
+ 4 u |
- 138 |
| After |
1 u |
6 u |
10 u |
Volume of water in Tank B at first before Michael poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Tank C at first before Michael tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Tank C at first before Michael poured out 138 mℓ of water
= 10 u + 138
Total volume of water in the three tanks at first
= 2 u + 2 u + 10 u + 138
= 14 u + 138
14 u + 138 = 236
14 u = 236 - 138
14 u = 98
1 u = 98 ÷ 14 = 7
Total volume of water in the three tanks now
= 1 u + 6 u + 10 u
= 17 u
= 17 x 7
= 119 mℓ
Answer(s): 119 mℓ
