The total volume of water in Tank Q, Tank R and Tank S was 244 mℓ. Ian poured out half the volume of water from Tank Q, doubled the amount of water in Tank R and added 86 mℓ of water into Tank S. The ratio of the volume of water in Tank Q to Tank R to Tank S is now 5 : 10 : 7. Find the total volume of water in the three tanks now.
| |
Q |
R |
S |
| Before |
10 u |
5 u |
7 u - 86 |
| Change |
- 5 u |
+ 5 u |
+ 86 |
| After |
5 u |
10 u |
7 u |
Volume of water in Tank Q at first before Tim poured out half the volume
= 2 x 5 u
= 10 u
Volume of water in Tank R at first before Tim doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Tank R at first before Tim added 86 mℓ of water
= 7 u - 86
Total volume of water in the three tanks at first
= 10 u + 5 u + 7 u - 86
= 22 u - 86
22 u - 86 = 244
22 u = 244 + 86
22 u = 330
1 u = 330 ÷ 22 = 15
Total volume of water in the three tanks now
= 5 u + 10 u + 7 u
= 22 u
= 22 x 15
= 330 mℓ
Answer(s): 330 mℓ
