The total volume of water in Tank R, Tank S and Tank T was 172 mℓ. Ian poured out half the volume of water from Tank R, tripled the amount of water in Tank S and poured out 60 mℓ of water from Tank T. The ratio of the volume of water in Tank R to Tank S to Tank T is now 5 : 3 : 5. Find the total volume of water in the three tanks now.
| |
R |
S |
T |
| Before |
10 u |
1 u |
5 u + 60 |
| Change |
- 5 u |
+ 2 u |
- 60 |
| After |
5 u |
3 u |
5 u |
Volume of water in Tank R at first before Zane poured out half the volume
= 2 x 5 u
= 10 u
Volume of water in Tank S at first before Zane tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Tank S at first before Zane poured out 60 mℓ of water
= 5 u + 60
Total volume of water in the three tanks at first
= 10 u + 1 u + 5 u + 60
= 16 u + 60
16 u + 60 = 172
16 u = 172 - 60
16 u = 112
1 u = 112 ÷ 16 = 7
Total volume of water in the three tanks now
= 5 u + 3 u + 5 u
= 13 u
= 13 x 7
= 91 mℓ
Answer(s): 91 mℓ
