The total volume of water in Bottle M, Bottle N and Bottle P was 313 mℓ. Ian poured out half the volume of water from Bottle M, tripled the amount of water in Bottle N and poured out 133 mℓ of water from Bottle P. The ratio of the volume of water in Bottle M to Bottle N to Bottle P is now 1 : 3 : 7. Find the total volume of water in the three bottles now.
|
M |
N |
P |
Before |
2 u |
1 u |
7 u + 133 |
Change |
- 1 u |
+ 2 u |
- 133 |
After |
1 u |
3 u |
7 u |
Volume of water in Bottle M at first before Luis poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Bottle N at first before Luis tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Bottle N at first before Luis poured out 133 mℓ of water
= 7 u + 133
Total volume of water in the three bottles at first
= 2 u + 1 u + 7 u + 133
= 10 u + 133
10 u + 133 = 313
10 u = 313 - 133
10 u = 180
1 u = 180 ÷ 10 = 18
Total volume of water in the three bottles now
= 1 u + 3 u + 7 u
= 11 u
= 11 x 18
= 198 mℓ
Answer(s): 198 mℓ