The total volume of water in Watering Can Q, Watering Can R and Watering Can S was 117 mℓ. Ian poured out half the volume of water from Watering Can Q, doubled the amount of water in Watering Can R and added 65 mℓ of water into Watering Can S. The ratio of the volume of water in Watering Can Q to Watering Can R to Watering Can S is now 1 : 10 : 7. Find the total volume of water in the three watering cans now.
| |
Q |
R |
S |
| Before |
2 u |
5 u |
7 u - 65 |
| Change |
- 1 u |
+ 5 u |
+ 65 |
| After |
1 u |
10 u |
7 u |
Volume of water in Watering Can Q at first before Flynn poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Watering Can R at first before Flynn doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Watering Can R at first before Flynn added 65 mℓ of water
= 7 u - 65
Total volume of water in the three watering cans at first
= 2 u + 5 u + 7 u - 65
= 14 u - 65
14 u - 65 = 117
14 u = 117 + 65
14 u = 182
1 u = 182 ÷ 14 = 13
Total volume of water in the three watering cans now
= 1 u + 10 u + 7 u
= 18 u
= 18 x 13
= 234 mℓ
Answer(s): 234 mℓ
