The total volume of water in Watering Can A, Watering Can B and Watering Can C was 97 mℓ. Ian poured out half the volume of water from Watering Can A, doubled the amount of water in Watering Can B and added 78 mℓ of water into Watering Can C. The ratio of the volume of water in Watering Can A to Watering Can B to Watering Can C is now 9 : 6 : 4. Find the total volume of water in the three watering cans now.
| |
A |
B |
C |
| Before |
18 u |
3 u |
4 u - 78 |
| Change |
- 9 u |
+ 3 u |
+ 78 |
| After |
9 u |
6 u |
4 u |
Volume of water in Watering Can A at first before Daniel poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Watering Can B at first before Daniel doubled the volume
= 6 u ÷ 2
= 3 u
Volume of water in Watering Can B at first before Daniel added 78 mℓ of water
= 4 u - 78
Total volume of water in the three watering cans at first
= 18 u + 3 u + 4 u - 78
= 25 u - 78
25 u - 78 = 97
25 u = 97 + 78
25 u = 175
1 u = 175 ÷ 25 = 7
Total volume of water in the three watering cans now
= 9 u + 6 u + 4 u
= 19 u
= 19 x 7
= 133 mℓ
Answer(s): 133 mℓ
