The total volume of water in Tank R, Tank S and Tank T was 382 mℓ. Ian poured out half the volume of water from Tank R, tripled the amount of water in Tank S and poured out 148 mℓ of water from Tank T. The ratio of the volume of water in Tank R to Tank S to Tank T is now 1 : 3 : 10. Find the total volume of water in the three tanks now.
| |
R |
S |
T |
| Before |
2 u |
1 u |
10 u + 148 |
| Change |
- 1 u |
+ 2 u |
- 148 |
| After |
1 u |
3 u |
10 u |
Volume of water in Tank R at first before Warren poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Tank S at first before Warren tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Tank S at first before Warren poured out 148 mℓ of water
= 10 u + 148
Total volume of water in the three tanks at first
= 2 u + 1 u + 10 u + 148
= 13 u + 148
13 u + 148 = 382
13 u = 382 - 148
13 u = 234
1 u = 234 ÷ 13 = 18
Total volume of water in the three tanks now
= 1 u + 3 u + 10 u
= 14 u
= 14 x 18
= 252 mℓ
Answer(s): 252 mℓ
