The total volume of water in Watering Can B, Watering Can C and Watering Can D was 92 mℓ. Ian poured out half the volume of water from Watering Can B, doubled the amount of water in Watering Can C and added 108 mℓ of water into Watering Can D. The ratio of the volume of water in Watering Can B to Watering Can C to Watering Can D is now 7 : 2 : 5. Find the total volume of water in the three watering cans now.
| |
B |
C |
D |
| Before |
14 u |
1 u |
5 u - 108 |
| Change |
- 7 u |
+ 1 u |
+ 108 |
| After |
7 u |
2 u |
5 u |
Volume of water in Watering Can B at first before Liam poured out half the volume
= 2 x 7 u
= 14 u
Volume of water in Watering Can C at first before Liam doubled the volume
= 2 u ÷ 2
= 1 u
Volume of water in Watering Can C at first before Liam added 108 mℓ of water
= 5 u - 108
Total volume of water in the three watering cans at first
= 14 u + 1 u + 5 u - 108
= 20 u - 108
20 u - 108 = 92
20 u = 92 + 108
20 u = 200
1 u = 200 ÷ 20 = 10
Total volume of water in the three watering cans now
= 7 u + 2 u + 5 u
= 14 u
= 14 x 10
= 140 mℓ
Answer(s): 140 mℓ
