The total volume of water in Watering Can L, Watering Can M and Watering Can N was 216 mℓ. Ian poured out half the volume of water from Watering Can L, tripled the amount of water in Watering Can M and poured out 90 mℓ of water from Watering Can N. The ratio of the volume of water in Watering Can L to Watering Can M to Watering Can N is now 1 : 9 : 4. Find the total volume of water in the three watering cans now.
| |
L |
M |
N |
| Before |
2 u |
3 u |
4 u + 90 |
| Change |
- 1 u |
+ 6 u |
- 90 |
| After |
1 u |
9 u |
4 u |
Volume of water in Watering Can L at first before Henry poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Watering Can M at first before Henry tripled the volume
= 9 u ÷ 3
= 3 u
Volume of water in Watering Can M at first before Henry poured out 90 mℓ of water
= 4 u + 90
Total volume of water in the three watering cans at first
= 2 u + 3 u + 4 u + 90
= 9 u + 90
9 u + 90 = 216
9 u = 216 - 90
9 u = 126
1 u = 126 ÷ 9 = 14
Total volume of water in the three watering cans now
= 1 u + 9 u + 4 u
= 14 u
= 14 x 14
= 196 mℓ
Answer(s): 196 mℓ
