The total volume of water in Tank N, Tank P and Tank Q was 185 mℓ. Ian poured out half the volume of water from Tank N, doubled the amount of water in Tank P and added 103 mℓ of water into Tank Q. The ratio of the volume of water in Tank N to Tank P to Tank Q is now 6 : 2 : 5. Find the total volume of water in the three tanks now.
|
N |
P |
Q |
Before |
12 u |
1 u |
5 u - 103 |
Change |
- 6 u |
+ 1 u |
+ 103 |
After |
6 u |
2 u |
5 u |
Volume of water in Tank N at first before Neave poured out half the volume
= 2 x 6 u
= 12 u
Volume of water in Tank P at first before Neave doubled the volume
= 2 u ÷ 2
= 1 u
Volume of water in Tank P at first before Neave added 103 mℓ of water
= 5 u - 103
Total volume of water in the three tanks at first
= 12 u + 1 u + 5 u - 103
= 18 u - 103
18 u - 103 = 185
18 u = 185 + 103
18 u = 288
1 u = 288 ÷ 18 = 16
Total volume of water in the three tanks now
= 6 u + 2 u + 5 u
= 13 u
= 13 x 16
= 208 mℓ
Answer(s): 208 mℓ