The total volume of water in Tank R, Tank S and Tank T was 274 mℓ. Ian poured out half the volume of water from Tank R, tripled the amount of water in Tank S and poured out 64 mℓ of water from Tank T. The ratio of the volume of water in Tank R to Tank S to Tank T is now 4 : 6 : 5. Find the total volume of water in the three tanks now.
| |
R |
S |
T |
| Before |
8 u |
2 u |
5 u + 64 |
| Change |
- 4 u |
+ 4 u |
- 64 |
| After |
4 u |
6 u |
5 u |
Volume of water in Tank R at first before George poured out half the volume
= 2 x 4 u
= 8 u
Volume of water in Tank S at first before George tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Tank S at first before George poured out 64 mℓ of water
= 5 u + 64
Total volume of water in the three tanks at first
= 8 u + 2 u + 5 u + 64
= 15 u + 64
15 u + 64 = 274
15 u = 274 - 64
15 u = 210
1 u = 210 ÷ 15 = 14
Total volume of water in the three tanks now
= 4 u + 6 u + 5 u
= 15 u
= 15 x 14
= 210 mℓ
Answer(s): 210 mℓ
