The total volume of water in Tank C, Tank D and Tank E was 87 mℓ. Ian poured out half the volume of water from Tank C, doubled the amount of water in Tank D and added 66 mℓ of water into Tank E. The ratio of the volume of water in Tank C to Tank D to Tank E is now 3 : 4 : 1. Find the total volume of water in the three tanks now.
| |
C |
D |
E |
| Before |
6 u |
2 u |
1 u - 66 |
| Change |
- 3 u |
+ 2 u |
+ 66 |
| After |
3 u |
4 u |
1 u |
Volume of water in Tank C at first before Liam poured out half the volume
= 2 x 3 u
= 6 u
Volume of water in Tank D at first before Liam doubled the volume
= 4 u ÷ 2
= 2 u
Volume of water in Tank D at first before Liam added 66 mℓ of water
= 1 u - 66
Total volume of water in the three tanks at first
= 6 u + 2 u + 1 u - 66
= 9 u - 66
9 u - 66 = 87
9 u = 87 + 66
9 u = 153
1 u = 153 ÷ 9 = 17
Total volume of water in the three tanks now
= 3 u + 4 u + 1 u
= 8 u
= 8 x 17
= 136 mℓ
Answer(s): 136 mℓ
