The total volume of water in Tank R, Tank S and Tank T was 216 mℓ. Ian poured out half the volume of water from Tank R, tripled the amount of water in Tank S and poured out 84 mℓ of water from Tank T. The ratio of the volume of water in Tank R to Tank S to Tank T is now 2 : 6 : 5. Find the total volume of water in the three tanks now.
|
R |
S |
T |
Before |
4 u |
2 u |
5 u + 84 |
Change |
- 2 u |
+ 4 u |
- 84 |
After |
2 u |
6 u |
5 u |
Volume of water in Tank R at first before Ken poured out half the volume
= 2 x 2 u
= 4 u
Volume of water in Tank S at first before Ken tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Tank S at first before Ken poured out 84 mℓ of water
= 5 u + 84
Total volume of water in the three tanks at first
= 4 u + 2 u + 5 u + 84
= 11 u + 84
11 u + 84 = 216
11 u = 216 - 84
11 u = 132
1 u = 132 ÷ 11 = 12
Total volume of water in the three tanks now
= 2 u + 6 u + 5 u
= 13 u
= 13 x 12
= 156 mℓ
Answer(s): 156 mℓ