The total volume of water in Tank L, Tank M and Tank N was 30 mℓ. Ian poured out half the volume of water from Tank L, doubled the amount of water in Tank M and added 110 mℓ of water into Tank N. The ratio of the volume of water in Tank L to Tank M to Tank N is now 9 : 2 : 1. Find the total volume of water in the three tanks now.
| |
L |
M |
N |
| Before |
18 u |
1 u |
1 u - 110 |
| Change |
- 9 u |
+ 1 u |
+ 110 |
| After |
9 u |
2 u |
1 u |
Volume of water in Tank L at first before Flynn poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Tank M at first before Flynn doubled the volume
= 2 u ÷ 2
= 1 u
Volume of water in Tank M at first before Flynn added 110 mℓ of water
= 1 u - 110
Total volume of water in the three tanks at first
= 18 u + 1 u + 1 u - 110
= 20 u - 110
20 u - 110 = 30
20 u = 30 + 110
20 u = 140
1 u = 140 ÷ 20 = 7
Total volume of water in the three tanks now
= 9 u + 2 u + 1 u
= 12 u
= 12 x 7
= 84 mℓ
Answer(s): 84 mℓ
