The total volume of water in Watering Can C, Watering Can D and Watering Can E was 350 mℓ. Ian poured out half the volume of water from Watering Can C, doubled the amount of water in Watering Can D and added 50 mℓ of water into Watering Can E. The ratio of the volume of water in Watering Can C to Watering Can D to Watering Can E is now 7 : 10 : 6. Find the total volume of water in the three watering cans now.
| |
C |
D |
E |
| Before |
14 u |
5 u |
6 u - 50 |
| Change |
- 7 u |
+ 5 u |
+ 50 |
| After |
7 u |
10 u |
6 u |
Volume of water in Watering Can C at first before Neave poured out half the volume
= 2 x 7 u
= 14 u
Volume of water in Watering Can D at first before Neave doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Watering Can D at first before Neave added 50 mℓ of water
= 6 u - 50
Total volume of water in the three watering cans at first
= 14 u + 5 u + 6 u - 50
= 25 u - 50
25 u - 50 = 350
25 u = 350 + 50
25 u = 400
1 u = 400 ÷ 25 = 16
Total volume of water in the three watering cans now
= 7 u + 10 u + 6 u
= 23 u
= 23 x 16
= 368 mℓ
Answer(s): 368 mℓ
