The total volume of water in Bottle B, Bottle C and Bottle D was 153 mℓ. Ian poured out half the volume of water from Bottle B, doubled the amount of water in Bottle C and added 56 mℓ of water into Bottle D. The ratio of the volume of water in Bottle B to Bottle C to Bottle D is now 4 : 8 : 7. Find the total volume of water in the three bottles now.
| |
B |
C |
D |
| Before |
8 u |
4 u |
7 u - 56 |
| Change |
- 4 u |
+ 4 u |
+ 56 |
| After |
4 u |
8 u |
7 u |
Volume of water in Bottle B at first before Xavier poured out half the volume
= 2 x 4 u
= 8 u
Volume of water in Bottle C at first before Xavier doubled the volume
= 8 u ÷ 2
= 4 u
Volume of water in Bottle C at first before Xavier added 56 mℓ of water
= 7 u - 56
Total volume of water in the three bottles at first
= 8 u + 4 u + 7 u - 56
= 19 u - 56
19 u - 56 = 153
19 u = 153 + 56
19 u = 209
1 u = 209 ÷ 19 = 11
Total volume of water in the three bottles now
= 4 u + 8 u + 7 u
= 19 u
= 19 x 11
= 209 mℓ
Answer(s): 209 mℓ
