The total volume of water in Tank J, Tank K and Tank L was 192 mℓ. Ian poured out half the volume of water from Tank J, tripled the amount of water in Tank K and poured out 137 mℓ of water from Tank L. The ratio of the volume of water in Tank J to Tank K to Tank L is now 2 : 6 : 5. Find the total volume of water in the three tanks now.
|
J |
K |
L |
Before |
4 u |
2 u |
5 u + 137 |
Change |
- 2 u |
+ 4 u |
- 137 |
After |
2 u |
6 u |
5 u |
Volume of water in Tank J at first before Howard poured out half the volume
= 2 x 2 u
= 4 u
Volume of water in Tank K at first before Howard tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Tank K at first before Howard poured out 137 mℓ of water
= 5 u + 137
Total volume of water in the three tanks at first
= 4 u + 2 u + 5 u + 137
= 11 u + 137
11 u + 137 = 192
11 u = 192 - 137
11 u = 55
1 u = 55 ÷ 11 = 5
Total volume of water in the three tanks now
= 2 u + 6 u + 5 u
= 13 u
= 13 x 5
= 65 mℓ
Answer(s): 65 mℓ