The total volume of water in Watering Can R, Watering Can S and Watering Can T was 125 mℓ. Ian poured out half the volume of water from Watering Can R, tripled the amount of water in Watering Can S and poured out 62 mℓ of water from Watering Can T. The ratio of the volume of water in Watering Can R to Watering Can S to Watering Can T is now 3 : 6 : 1. Find the total volume of water in the three watering cans now.
| |
R |
S |
T |
| Before |
6 u |
2 u |
1 u + 62 |
| Change |
- 3 u |
+ 4 u |
- 62 |
| After |
3 u |
6 u |
1 u |
Volume of water in Watering Can R at first before Jenson poured out half the volume
= 2 x 3 u
= 6 u
Volume of water in Watering Can S at first before Jenson tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Watering Can S at first before Jenson poured out 62 mℓ of water
= 1 u + 62
Total volume of water in the three watering cans at first
= 6 u + 2 u + 1 u + 62
= 9 u + 62
9 u + 62 = 125
9 u = 125 - 62
9 u = 63
1 u = 63 ÷ 9 = 7
Total volume of water in the three watering cans now
= 3 u + 6 u + 1 u
= 10 u
= 10 x 7
= 70 mℓ
Answer(s): 70 mℓ
