The total volume of water in Watering Can B, Watering Can C and Watering Can D was 494 mℓ. Ian poured out half the volume of water from Watering Can B, doubled the amount of water in Watering Can C and added 64 mℓ of water into Watering Can D. The ratio of the volume of water in Watering Can B to Watering Can C to Watering Can D is now 9 : 10 : 8. Find the total volume of water in the three watering cans now.
| |
B |
C |
D |
| Before |
18 u |
5 u |
8 u - 64 |
| Change |
- 9 u |
+ 5 u |
+ 64 |
| After |
9 u |
10 u |
8 u |
Volume of water in Watering Can B at first before Tommy poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Watering Can C at first before Tommy doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Watering Can C at first before Tommy added 64 mℓ of water
= 8 u - 64
Total volume of water in the three watering cans at first
= 18 u + 5 u + 8 u - 64
= 31 u - 64
31 u - 64 = 494
31 u = 494 + 64
31 u = 558
1 u = 558 ÷ 31 = 18
Total volume of water in the three watering cans now
= 9 u + 10 u + 8 u
= 27 u
= 27 x 18
= 486 mℓ
Answer(s): 486 mℓ
