Shiyun, Raeann and Marion had a total of 86 stickers. The ratio of Raeann's stickers to Marion's stickers was at first 10 : 3. After Shiyun and Raeann each gave half of their stickers away, the 3 children had 49 stickers left. How many stickers did Shiyun and Raeann have at first?
|
Shiyun |
Raeann |
Marion |
Total |
Before |
2 p |
10 u |
3 u |
86 |
Change |
- 1 p |
- 5 u |
|
- 37 |
After |
1 p |
5 u |
3 u |
49 |
Number of stickers that Shiyun and Raeann gave away
= 86 - 49
= 37
1 p + 5 u = 37
1 p = 37 - 5 u --- (1)
1 p + 5 u + 3 u = 49
1 p + 8 u = 49
1 p = 49 - 8 u --- (2)
(1) = (2)
37 - 5 u = 49 - 8 u
8 u - 5 u = 49 - 37
3 u = 12
1 u = 12 ÷ 3 = 4
From (1)
1 p = 37 - 5 u
1 p = 37 - 5 x 4
1 p = 37 - 20 = 17
Number of stickers that Shiyun and Raeann had at first
= 2 p + 10 u
= 2 x 17 + 10 x 4
= 34 + 12
= 46
Answer(s): 46