Anna, Pamela and Natalie had a total of 127 marbles. The ratio of Pamela's marbles to Natalie's marbles was at first 12 : 7. After Anna and Pamela each gave half of their marbles away, the 3 children had 81 marbles left. How many marbles did Anna and Pamela have at first?
|
Anna |
Pamela |
Natalie |
Total |
Before |
2 p |
12 u |
7 u |
127 |
Change |
- 1 p |
- 6 u |
|
- 46 |
After |
1 p |
6 u |
7 u |
81 |
Number of marbles that Anna and Pamela gave away
= 127 - 81
= 46
1 p + 6 u = 46
1 p = 46 - 6 u --- (1)
1 p + 6 u + 7 u = 81
1 p + 13 u = 81
1 p = 81 - 13 u --- (2)
(1) = (2)
46 - 6 u = 81 - 13 u
13 u - 6 u = 81 - 46
7 u = 35
1 u = 35 ÷ 7 = 5
From (1)
1 p = 46 - 6 u
1 p = 46 - 6 x 5
1 p = 46 - 30 = 16
Number of marbles that Anna and Pamela had at first
= 2 p + 12 u
= 2 x 16 + 12 x 5
= 32 + 35
= 67
Answer(s): 67