Sabrina, Kathy and Usha had a total of 81 marbles. The ratio of Kathy's marbles to Usha's marbles was at first 10 : 7. After Sabrina and Kathy each gave half of their marbles away, the 3 children had 51 marbles left. How many marbles did Sabrina and Kathy have at first?
|
Sabrina |
Kathy |
Usha |
Total |
Before |
2 p |
10 u |
7 u |
81 |
Change |
- 1 p |
- 5 u |
|
- 30 |
After |
1 p |
5 u |
7 u |
51 |
Number of marbles that Sabrina and Kathy gave away
= 81 - 51
= 30
1 p + 5 u = 30
1 p = 30 - 5 u --- (1)
1 p + 5 u + 7 u = 51
1 p + 12 u = 51
1 p = 51 - 12 u --- (2)
(1) = (2)
30 - 5 u = 51 - 12 u
12 u - 5 u = 51 - 30
7 u = 21
1 u = 21 ÷ 7 = 3
From (1)
1 p = 30 - 5 u
1 p = 30 - 5 x 3
1 p = 30 - 15 = 15
Number of marbles that Sabrina and Kathy had at first
= 2 p + 10 u
= 2 x 15 + 10 x 3
= 30 + 21
= 51
Answer(s): 51