Emma, Hilda and Joelle had a total of 151 stickers. The ratio of Hilda's stickers to Joelle's stickers was at first 8 : 3. After Emma and Hilda each gave half of their stickers away, the 3 children had 92 stickers left. How many stickers did Emma and Joelle have at first?
| |
Emma |
Hilda |
Joelle |
Total |
| Before |
2 p |
8 u |
3 u |
151 |
| Change |
- 1 p |
- 4 u |
|
- 59 |
| After |
1 p |
4 u |
3 u |
92 |
Number of stickers that Emma and Hilda gave away
= 151 - 92
= 59
1 p + 4 u = 59
1 p = 59 - 4 u --- (1)
1 p + 4 u + 3 u = 92
1 p + 7 u = 92
1 p = 92 - 7 u --- (2)
(1) = (2)
59 - 4 u = 92 - 7 u
7 u - 4 u = 92 - 59
3 u = 33
1 u = 33 ÷ 3 = 11
From (1)
1 p = 59 - 4 u
1 p = 59 - 4 x 11
1 p = 59 - 44 = 15
Number of stickers that Emma and Joelle had at first
= 2 p + 3 u
= 2 x 15 + 3 x 11
= 30 + 33
= 63
Answer(s): 63
