In a container, there are jelly beans of 3 colours, brown, black and red. There are 132 less red jelly beans than black jelly beans. The number of red jelly beans is ¹₂ more than the brown jelly beans. Given that the number of red jelly beans is 21% of the total number of jelly beans in the container, how many less brown jelly beans are there than black jelly beans?

Brown jelly beans	Black jelly beans	Red jelly beans
	1 u + 132	1 u
2x7		3x7
79%		21%
14%	65%	21%

1 + ¹₂ = ²₂ + ¹₂ = ³₂

Yellow jelly beans : Purple jelly beans = 2 : 3

The number of red jelly beans is repeated.  Make the number of red jelly beans the same.

3 x 7 = 21%

Total number of brown jelly beans and black jelly beans in percent
= 100% - 21%
= 79%

Number of black jelly beans in percent
= 79% - 14%
= 65%

Number of more black jelly beans than red jelly beans in percent
= 65% - 14%
= 44%

44% = 132

1% = 132 ÷ 44 = 3

Number of less brown jelly beans than black jelly beans
= 65% - 14%
= 51%
= 51 x 3
= 153

Answer(s): 153