In a container, there are sweets of 3 colours, green, red and black. There are 54 more red sweets than black sweets. The number of black sweets is ²₃ more than the green sweets. Given that the number of black sweets is 35% of the total number of sweets in the container, how many more red sweets are there than green sweets?

Green sweets	Red sweets	Black sweets
	1 u + 54	1 u
3x7		5x7
65%		35%
21%	44%	35%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow sweets : Purple sweets = 3 : 5

The number of black sweets is repeated.  Make the number of black sweets the same.

5 x 7 = 35%

Total number of green sweets and red sweets in percent
= 100% - 35%
= 65%

Number of red sweets in percent
= 65% - 21%
= 44%

Number of more red sweets than black sweets in percent
= 44% - 21%
= 9%

9% = 54

1% = 54 ÷ 9 = 6

Number of more red sweets than green sweets
= 44% - 21%
= 23%
= 23 x 6
= 138

Answer(s): 138