In a container, there are chocolate bars of 3 colours, red, blue and silver. There are 201 more blue chocolate bars than silver chocolate bars. The number of silver chocolate bars is ¹₃ more than the red chocolate bars. Given that the number of silver chocolate bars is 12% of the total number of chocolate bars in the container, how many more blue chocolate bars are there than red chocolate bars?

Red chocolate bars	Blue chocolate bars	Silver chocolate bars
	1 u + 201	1 u
3x3		4x3
88%		12%
9%	79%	12%

1 + ¹₃ = ³₃ + ¹₃ = ⁴₃

Yellow chocolate bars : Purple chocolate bars = 3 : 4

The number of silver chocolate bars is repeated.  Make the number of silver chocolate bars the same.

4 x 3 = 12%

Total number of red chocolate bars and blue chocolate bars in percent
= 100% - 12%
= 88%

Number of blue chocolate bars in percent
= 88% - 9%
= 79%

Number of more blue chocolate bars than silver chocolate bars in percent
= 79% - 9%
= 67%

67% = 201

1% = 201 ÷ 67 = 3

Number of more blue chocolate bars than red chocolate bars
= 79% - 9%
= 70%
= 70 x 3
= 210

Answer(s): 210