In a box, there are sweets of 3 colours, brown, white and silver. There are 116 less silver sweets than white sweets. The number of silver sweets is ¹₄ more than the brown sweets. Given that the number of silver sweets is 15% of the total number of sweets in the box, how many less brown sweets are there than white sweets?

Brown sweets	White sweets	Silver sweets
	1 u + 116	1 u
4x3		5x3
85%		15%
12%	73%	15%

1 + ¹₄ = ⁴₄ + ¹₄ = ⁵₄

Yellow sweets : Purple sweets = 4 : 5

The number of silver sweets is repeated.  Make the number of silver sweets the same.

5 x 3 = 15%

Total number of brown sweets and white sweets in percent
= 100% - 15%
= 85%

Number of white sweets in percent
= 85% - 12%
= 73%

Number of more white sweets than silver sweets in percent
= 73% - 12%
= 58%

58% = 116

1% = 116 ÷ 58 = 2

Number of less brown sweets than white sweets
= 73% - 12%
= 61%
= 61 x 2
= 122

Answer(s): 122