In a container, there are candy canes of 3 colours, silver, red and blue. There are 468 less blue candy canes than red candy canes. The number of blue candy canes is
12 more than the silver candy canes. Given that the number of blue candy canes is 18% of the total number of candy canes in the container, how many less silver candy canes are there than red candy canes?
Silver candy canes |
Red candy canes |
Blue candy canes |
|
1 u + 468 |
1 u |
2x6 |
|
3x6 |
82% |
18% |
12% |
70% |
18% |
1 +
12 =
22 +
12 =
32 Yellow candy canes : Purple candy canes = 2 : 3
The number of blue candy canes is repeated. Make the number of blue candy canes the same.
3 x 6 = 18%
Total number of silver candy canes and red candy canes in percent
= 100% - 18%
= 82%
Number of red candy canes in percent
= 82% - 12%
= 70%
Number of more red candy canes than blue candy canes in percent
= 70% - 12%
= 52%
52% = 468
1% = 468 ÷ 52 = 9
Number of less silver candy canes than red candy canes
= 70% - 12%
= 58%
= 58 x 9
= 522
Answer(s): 522