In a container, there are sweets of 3 colours, yellow, green and brown. There are 441 less brown sweets than green sweets. The number of brown sweets is
15 more than the yellow sweets. Given that the number of brown sweets is 18% of the total number of sweets in the container, how many less yellow sweets are there than green sweets?
Yellow sweets |
Green sweets |
Brown sweets |
|
1 u + 441 |
1 u |
5x3 |
|
6x3 |
82% |
18% |
15% |
67% |
18% |
1 +
15 =
55 +
15 =
65 Yellow sweets : Purple sweets = 5 : 6
The number of brown sweets is repeated. Make the number of brown sweets the same.
6 x 3 = 18%
Total number of yellow sweets and green sweets in percent
= 100% - 18%
= 82%
Number of green sweets in percent
= 82% - 15%
= 67%
Number of more green sweets than brown sweets in percent
= 67% - 15%
= 49%
49% = 441
1% = 441 ÷ 49 = 9
Number of less yellow sweets than green sweets
= 67% - 15%
= 52%
= 52 x 9
= 468
Answer(s): 468