In a container, there are sweets of 3 colours, silver, red and yellow. There are 260 less yellow sweets than red sweets. The number of yellow sweets is
12 more than the silver sweets. Given that the number of yellow sweets is 18% of the total number of sweets in the container, how many less silver sweets are there than red sweets?
Silver sweets |
Red sweets |
Yellow sweets |
|
1 u + 260 |
1 u |
2x6 |
|
3x6 |
82% |
18% |
12% |
70% |
18% |
1 +
12 =
22 +
12 =
32 Yellow sweets : Purple sweets = 2 : 3
The number of yellow sweets is repeated. Make the number of yellow sweets the same.
3 x 6 = 18%
Total number of silver sweets and red sweets in percent
= 100% - 18%
= 82%
Number of red sweets in percent
= 82% - 12%
= 70%
Number of more red sweets than yellow sweets in percent
= 70% - 12%
= 52%
52% = 260
1% = 260 ÷ 52 = 5
Number of less silver sweets than red sweets
= 70% - 12%
= 58%
= 58 x 5
= 290
Answer(s): 290