In a container, there are sweets of 3 colours, pink, red and green. There are 520 less green sweets than red sweets. The number of green sweets is
12 more than the pink sweets. Given that the number of green sweets is 18% of the total number of sweets in the container, how many less pink sweets are there than red sweets?
Pink sweets |
Red sweets |
Green sweets |
|
1 u + 520 |
1 u |
2x6 |
|
3x6 |
82% |
18% |
12% |
70% |
18% |
1 +
12 =
22 +
12 =
32 Yellow sweets : Purple sweets = 2 : 3
The number of green sweets is repeated. Make the number of green sweets the same.
3 x 6 = 18%
Total number of pink sweets and red sweets in percent
= 100% - 18%
= 82%
Number of red sweets in percent
= 82% - 12%
= 70%
Number of more red sweets than green sweets in percent
= 70% - 12%
= 52%
52% = 520
1% = 520 ÷ 52 = 10
Number of less pink sweets than red sweets
= 70% - 12%
= 58%
= 58 x 10
= 580
Answer(s): 580