In a box, there are candy canes of 3 colours, black, white and silver. There are 96 less silver candy canes than white candy canes. The number of silver candy canes is ²₃ more than the black candy canes. Given that the number of silver candy canes is 20% of the total number of candy canes in the box, how many less black candy canes are there than white candy canes?

Black candy canes	White candy canes	Silver candy canes
	1 u + 96	1 u
3x4		5x4
80%		20%
12%	68%	20%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow candy canes : Purple candy canes = 3 : 5

The number of silver candy canes is repeated.  Make the number of silver candy canes the same.

5 x 4 = 20%

Total number of black candy canes and white candy canes in percent
= 100% - 20%
= 80%

Number of white candy canes in percent
= 80% - 12%
= 68%

Number of more white candy canes than silver candy canes in percent
= 68% - 12%
= 48%

48% = 96

1% = 96 ÷ 48 = 2

Number of less black candy canes than white candy canes
= 68% - 12%
= 56%
= 56 x 2
= 112

Answer(s): 112