In a box, there are chocolate bars of 3 colours, gold, silver and black. There are 122 more silver chocolate bars than black chocolate bars. The number of black chocolate bars is ²₃ more than the gold chocolate bars. Given that the number of black chocolate bars is 15% of the total number of chocolate bars in the box, how many more silver chocolate bars are there than gold chocolate bars?

Gold chocolate bars	Silver chocolate bars	Black chocolate bars
	1 u + 122	1 u
3x3		5x3
85%		15%
9%	76%	15%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow chocolate bars : Purple chocolate bars = 3 : 5

The number of black chocolate bars is repeated.  Make the number of black chocolate bars the same.

5 x 3 = 15%

Total number of gold chocolate bars and silver chocolate bars in percent
= 100% - 15%
= 85%

Number of silver chocolate bars in percent
= 85% - 9%
= 76%

Number of more silver chocolate bars than black chocolate bars in percent
= 76% - 9%
= 61%

61% = 122

1% = 122 ÷ 61 = 2

Number of more silver chocolate bars than gold chocolate bars
= 76% - 9%
= 67%
= 67 x 2
= 134

Answer(s): 134