In a container, there are sweets of 3 colours, blue, yellow and red. There are 136 more yellow sweets than red sweets. The number of red sweets is ¹₂ more than the blue sweets. Given that the number of red sweets is 12% of the total number of sweets in the container, how many more yellow sweets are there than blue sweets?

Blue sweets	Yellow sweets	Red sweets
	1 u + 136	1 u
2x4		3x4
88%		12%
8%	80%	12%

1 + ¹₂ = ²₂ + ¹₂ = ³₂

Yellow sweets : Purple sweets = 2 : 3

The number of red sweets is repeated.  Make the number of red sweets the same.

3 x 4 = 12%

Total number of blue sweets and yellow sweets in percent
= 100% - 12%
= 88%

Number of yellow sweets in percent
= 88% - 8%
= 80%

Number of more yellow sweets than red sweets in percent
= 80% - 8%
= 68%

68% = 136

1% = 136 ÷ 68 = 2

Number of more yellow sweets than blue sweets
= 80% - 8%
= 72%
= 72 x 2
= 144

Answer(s): 144