In a container, there are sweets of 3 colours, red, brown and green. There are 392 more brown sweets than green sweets. The number of green sweets is
13 more than the red sweets. Given that the number of green sweets is 16% of the total number of sweets in the container, how many more brown sweets are there than red sweets?
Red sweets |
Brown sweets |
Green sweets |
|
1 u + 392 |
1 u |
3x4 |
|
4x4 |
84% |
16% |
12% |
72% |
16% |
1 +
13 =
33 +
13 =
43 Yellow sweets : Purple sweets = 3 : 4
The number of green sweets is repeated. Make the number of green sweets the same.
4 x 4 = 16%
Total number of red sweets and brown sweets in percent
= 100% - 16%
= 84%
Number of brown sweets in percent
= 84% - 12%
= 72%
Number of more brown sweets than green sweets in percent
= 72% - 12%
= 56%
56% = 392
1% = 392 ÷ 56 = 7
Number of more brown sweets than red sweets
= 72% - 12%
= 60%
= 60 x 7
= 420
Answer(s): 420