In a container, there are candy canes of 3 colours, black, red and silver. There are 308 less silver candy canes than red candy canes. The number of silver candy canes is
14 more than the black candy canes. Given that the number of silver candy canes is 20% of the total number of candy canes in the container, how many less black candy canes are there than red candy canes?
Black candy canes |
Red candy canes |
Silver candy canes |
|
1 u + 308 |
1 u |
4x4 |
|
5x4 |
80% |
20% |
16% |
64% |
20% |
1 +
14 =
44 +
14 =
54 Yellow candy canes : Purple candy canes = 4 : 5
The number of silver candy canes is repeated. Make the number of silver candy canes the same.
5 x 4 = 20%
Total number of black candy canes and red candy canes in percent
= 100% - 20%
= 80%
Number of red candy canes in percent
= 80% - 16%
= 64%
Number of more red candy canes than silver candy canes in percent
= 64% - 16%
= 44%
44% = 308
1% = 308 ÷ 44 = 7
Number of less black candy canes than red candy canes
= 64% - 16%
= 48%
= 48 x 7
= 336
Answer(s): 336