In a container, there are chocolate bars of 3 colours, blue, red and silver. There are 180 more red chocolate bars than silver chocolate bars. The number of silver chocolate bars is
13 more than the blue chocolate bars. Given that the number of silver chocolate bars is 20% of the total number of chocolate bars in the container, how many more red chocolate bars are there than blue chocolate bars?
Blue chocolate bars |
Red chocolate bars |
Silver chocolate bars |
|
1 u + 180 |
1 u |
3x5 |
|
4x5 |
80% |
20% |
15% |
65% |
20% |
1 +
13 =
33 +
13 =
43 Yellow chocolate bars : Purple chocolate bars = 3 : 4
The number of silver chocolate bars is repeated. Make the number of silver chocolate bars the same.
4 x 5 = 20%
Total number of blue chocolate bars and red chocolate bars in percent
= 100% - 20%
= 80%
Number of red chocolate bars in percent
= 80% - 15%
= 65%
Number of more red chocolate bars than silver chocolate bars in percent
= 65% - 15%
= 45%
45% = 180
1% = 180 ÷ 45 = 4
Number of more red chocolate bars than blue chocolate bars
= 65% - 15%
= 50%
= 50 x 4
= 200
Answer(s): 200