In a box, there are sweets of 3 colours, red, black and white. There are 336 more black sweets than white sweets. The number of white sweets is
13 more than the red sweets. Given that the number of white sweets is 16% of the total number of sweets in the box, how many more black sweets are there than red sweets?
Red sweets |
Black sweets |
White sweets |
|
1 u + 336 |
1 u |
3x4 |
|
4x4 |
84% |
16% |
12% |
72% |
16% |
1 +
13 =
33 +
13 =
43 Yellow sweets : Purple sweets = 3 : 4
The number of white sweets is repeated. Make the number of white sweets the same.
4 x 4 = 16%
Total number of red sweets and black sweets in percent
= 100% - 16%
= 84%
Number of black sweets in percent
= 84% - 12%
= 72%
Number of more black sweets than white sweets in percent
= 72% - 12%
= 56%
56% = 336
1% = 336 ÷ 56 = 6
Number of more black sweets than red sweets
= 72% - 12%
= 60%
= 60 x 6
= 360
Answer(s): 360