In a box, there are chocolate bars of 3 colours, green, red and white. There are 384 more red chocolate bars than white chocolate bars. The number of white chocolate bars is ²₃ more than the green chocolate bars. Given that the number of white chocolate bars is 20% of the total number of chocolate bars in the box, how many more red chocolate bars are there than green chocolate bars?

Green chocolate bars	Red chocolate bars	White chocolate bars
	1 u + 384	1 u
3x4		5x4
80%		20%
12%	68%	20%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow chocolate bars : Purple chocolate bars = 3 : 5

The number of white chocolate bars is repeated.  Make the number of white chocolate bars the same.

5 x 4 = 20%

Total number of green chocolate bars and red chocolate bars in percent
= 100% - 20%
= 80%

Number of red chocolate bars in percent
= 80% - 12%
= 68%

Number of more red chocolate bars than white chocolate bars in percent
= 68% - 12%
= 48%

48% = 384

1% = 384 ÷ 48 = 8

Number of more red chocolate bars than green chocolate bars
= 68% - 12%
= 56%
= 56 x 8
= 448

Answer(s): 448