In a container, there are jelly beans of 3 colours, black, silver and purple. There are 176 less purple jelly beans than silver jelly beans. The number of purple jelly beans is ¹₄ more than the black jelly beans. Given that the number of purple jelly beans is 20% of the total number of jelly beans in the container, how many less black jelly beans are there than silver jelly beans?

Black jelly beans	Silver jelly beans	Purple jelly beans
	1 u + 176	1 u
4x4		5x4
80%		20%
16%	64%	20%

1 + ¹₄ = ⁴₄ + ¹₄ = ⁵₄

Yellow jelly beans : Purple jelly beans = 4 : 5

The number of purple jelly beans is repeated.  Make the number of purple jelly beans the same.

5 x 4 = 20%

Total number of black jelly beans and silver jelly beans in percent
= 100% - 20%
= 80%

Number of silver jelly beans in percent
= 80% - 16%
= 64%

Number of more silver jelly beans than purple jelly beans in percent
= 64% - 16%
= 44%

44% = 176

1% = 176 ÷ 44 = 4

Number of less black jelly beans than silver jelly beans
= 64% - 16%
= 48%
= 48 x 4
= 192

Answer(s): 192