In a box, there are sweets of 3 colours, yellow, white and brown. There are 396 less brown sweets than white sweets. The number of brown sweets is
12 more than the yellow sweets. Given that the number of brown sweets is 21% of the total number of sweets in the box, how many less yellow sweets are there than white sweets?
Yellow sweets |
White sweets |
Brown sweets |
|
1 u + 396 |
1 u |
2x7 |
|
3x7 |
79% |
21% |
14% |
65% |
21% |
1 +
12 =
22 +
12 =
32 Yellow sweets : Purple sweets = 2 : 3
The number of brown sweets is repeated. Make the number of brown sweets the same.
3 x 7 = 21%
Total number of yellow sweets and white sweets in percent
= 100% - 21%
= 79%
Number of white sweets in percent
= 79% - 14%
= 65%
Number of more white sweets than brown sweets in percent
= 65% - 14%
= 44%
44% = 396
1% = 396 ÷ 44 = 9
Number of less yellow sweets than white sweets
= 65% - 14%
= 51%
= 51 x 9
= 459
Answer(s): 459