In a box, there are sweets of 3 colours, red, grey and green. There are 160 less green sweets than grey sweets. The number of green sweets is
15 more than the red sweets. Given that the number of green sweets is 24% of the total number of sweets in the box, how many less red sweets are there than grey sweets?
Red sweets |
Grey sweets |
Green sweets |
|
1 u + 160 |
1 u |
5x4 |
|
6x4 |
76% |
24% |
20% |
56% |
24% |
1 +
15 =
55 +
15 =
65 Yellow sweets : Purple sweets = 5 : 6
The number of green sweets is repeated. Make the number of green sweets the same.
6 x 4 = 24%
Total number of red sweets and grey sweets in percent
= 100% - 24%
= 76%
Number of grey sweets in percent
= 76% - 20%
= 56%
Number of more grey sweets than green sweets in percent
= 56% - 20%
= 32%
32% = 160
1% = 160 ÷ 32 = 5
Number of less red sweets than grey sweets
= 56% - 20%
= 36%
= 36 x 5
= 180
Answer(s): 180