In a box, there are candy canes of 3 colours, silver, brown and red. There are 408 less red candy canes than brown candy canes. The number of red candy canes is
12 more than the silver candy canes. Given that the number of red candy canes is 12% of the total number of candy canes in the box, how many less silver candy canes are there than brown candy canes?
Silver candy canes |
Brown candy canes |
Red candy canes |
|
1 u + 408 |
1 u |
2x4 |
|
3x4 |
88% |
12% |
8% |
80% |
12% |
1 +
12 =
22 +
12 =
32 Yellow candy canes : Purple candy canes = 2 : 3
The number of red candy canes is repeated. Make the number of red candy canes the same.
3 x 4 = 12%
Total number of silver candy canes and brown candy canes in percent
= 100% - 12%
= 88%
Number of brown candy canes in percent
= 88% - 8%
= 80%
Number of more brown candy canes than red candy canes in percent
= 80% - 8%
= 68%
68% = 408
1% = 408 ÷ 68 = 6
Number of less silver candy canes than brown candy canes
= 80% - 8%
= 72%
= 72 x 6
= 432
Answer(s): 432