In a box, there are sweets of 3 colours, red, grey and green. There are 760 less green sweets than grey sweets. The number of green sweets is ¹₂ more than the red sweets. Given that the number of green sweets is 9% of the total number of sweets in the box, how many less red sweets are there than grey sweets?

Red sweets	Grey sweets	Green sweets
	1 u + 760	1 u
2x3		3x3
91%		9%
6%	85%	9%

1 + ¹₂ = ²₂ + ¹₂ = ³₂

Yellow sweets : Purple sweets = 2 : 3

The number of green sweets is repeated.  Make the number of green sweets the same.

3 x 3 = 9%

Total number of red sweets and grey sweets in percent
= 100% - 9%
= 91%

Number of grey sweets in percent
= 91% - 6%
= 85%

Number of more grey sweets than green sweets in percent
= 85% - 6%
= 76%

76% = 760

1% = 760 ÷ 76 = 10

Number of less red sweets than grey sweets
= 85% - 6%
= 79%
= 79 x 10
= 790

Answer(s): 790