In a container, there are chocolate bars of 3 colours, blue, silver and green. There are 348 less green chocolate bars than silver chocolate bars. The number of green chocolate bars is ¹₄ more than the blue chocolate bars. Given that the number of green chocolate bars is 15% of the total number of chocolate bars in the container, how many less blue chocolate bars are there than silver chocolate bars?

Blue chocolate bars	Silver chocolate bars	Green chocolate bars
	1 u + 348	1 u
4x3		5x3
85%		15%
12%	73%	15%

1 + ¹₄ = ⁴₄ + ¹₄ = ⁵₄

Yellow chocolate bars : Purple chocolate bars = 4 : 5

The number of green chocolate bars is repeated.  Make the number of green chocolate bars the same.

5 x 3 = 15%

Total number of blue chocolate bars and silver chocolate bars in percent
= 100% - 15%
= 85%

Number of silver chocolate bars in percent
= 85% - 12%
= 73%

Number of more silver chocolate bars than green chocolate bars in percent
= 73% - 12%
= 58%

58% = 348

1% = 348 ÷ 58 = 6

Number of less blue chocolate bars than silver chocolate bars
= 73% - 12%
= 61%
= 61 x 6
= 366

Answer(s): 366