In a container, there are sweets of 3 colours, blue, pink and brown. There are 608 less brown sweets than pink sweets. The number of brown sweets is
12 more than the blue sweets. Given that the number of brown sweets is 9% of the total number of sweets in the container, how many less blue sweets are there than pink sweets?
Blue sweets |
Pink sweets |
Brown sweets |
|
1 u + 608 |
1 u |
2x3 |
|
3x3 |
91% |
9% |
6% |
85% |
9% |
1 +
12 =
22 +
12 =
32 Yellow sweets : Purple sweets = 2 : 3
The number of brown sweets is repeated. Make the number of brown sweets the same.
3 x 3 = 9%
Total number of blue sweets and pink sweets in percent
= 100% - 9%
= 91%
Number of pink sweets in percent
= 91% - 6%
= 85%
Number of more pink sweets than brown sweets in percent
= 85% - 6%
= 76%
76% = 608
1% = 608 ÷ 76 = 8
Number of less blue sweets than pink sweets
= 85% - 6%
= 79%
= 79 x 8
= 632
Answer(s): 632