In a container, there are sweets of 3 colours, red, black and blue. There are 122 less blue sweets than black sweets. The number of blue sweets is ²₃ more than the red sweets. Given that the number of blue sweets is 15% of the total number of sweets in the container, how many less red sweets are there than black sweets?

Red sweets	Black sweets	Blue sweets
	1 u + 122	1 u
3x3		5x3
85%		15%
9%	76%	15%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow sweets : Purple sweets = 3 : 5

The number of blue sweets is repeated.  Make the number of blue sweets the same.

5 x 3 = 15%

Total number of red sweets and black sweets in percent
= 100% - 15%
= 85%

Number of black sweets in percent
= 85% - 9%
= 76%

Number of more black sweets than blue sweets in percent
= 76% - 9%
= 61%

61% = 122

1% = 122 ÷ 61 = 2

Number of less red sweets than black sweets
= 76% - 9%
= 67%
= 67 x 2
= 134

Answer(s): 134