In a container, there are chocolate bars of 3 colours, silver, green and brown. There are 6 more green chocolate bars than brown chocolate bars. The number of brown chocolate bars is
14 more than the silver chocolate bars. Given that the number of brown chocolate bars is 35% of the total number of chocolate bars in the container, how many more green chocolate bars are there than silver chocolate bars?
Silver chocolate bars |
Green chocolate bars |
Brown chocolate bars |
|
1 u + 6 |
1 u |
4x7 |
|
5x7 |
65% |
35% |
28% |
37% |
35% |
1 +
14 =
44 +
14 =
54 Yellow chocolate bars : Purple chocolate bars = 4 : 5
The number of brown chocolate bars is repeated. Make the number of brown chocolate bars the same.
5 x 7 = 35%
Total number of silver chocolate bars and green chocolate bars in percent
= 100% - 35%
= 65%
Number of green chocolate bars in percent
= 65% - 28%
= 37%
Number of more green chocolate bars than brown chocolate bars in percent
= 37% - 28%
= 2%
2% = 6
1% = 6 ÷ 2 = 3
Number of more green chocolate bars than silver chocolate bars
= 37% - 28%
= 9%
= 9 x 3
= 27
Answer(s): 27