The average number of starfruits in Container D, Container E and Container F is 26 and it is 2 more than the average number of kiwis in the 3 containers. ¹₆ of the kiwis are in Container D and the kiwis in Container D is 80% of the number of kiwis in Container E. If each container has the same number of fruits, what percentage of the fruits in Container F are starfruits?
Average number of kiwis
= 26 - 2
= 24

Total number of kiwis
= 3 x 24
= 72

Total number of starfruits
= 3 x 26 
= 78

Total number of fruits
= 72 + 78
= 150

Number of fruits in each container
= 150 ÷ 3
= 50

Kiwis in Container D	Kiwis in Container E	Kiwis in Container F	Total kiwis
1x4	5x4		6x4
4x1	5x1
4 u	5 u	15 u	24 u

80% = ⁸⁰₁₀₀ = ⁴₅

The number of kiwis in Container D is repeated.  Make the number of kiwis in Container D the same.  LCM of 1 and 4 is 4. 

Total number of kiwis
= 4 u + 5 u + 15 u
= 24 u

24 u = 72

1 u = 72 ÷ 24 = 3

Number of kiwis in Container F
= 15 u
= 15 x 3
= 45

Number of starfruits in Container F
= 50 - 45
= 5

Percentage of the fruits in Container F are starfruits
= ⁵₅₀ x 100%
= 10%

Answer(s): 10%