The average number of oranges in Container K, Container L and Container M is 18 and it is 6 more than the average number of pears in the 3 containers. ¹₆ of the pears are in Container K and the pears in Container K is 40% of the number of pears in Container L. If each container has the same number of fruits, what percentage of the fruits in Container M are oranges?
Average number of pears
= 18 - 6
= 12

Total number of pears
= 3 x 12
= 36

Total number of oranges
= 3 x 18 
= 54

Total number of fruits
= 36 + 54
= 90

Number of fruits in each container
= 90 ÷ 3
= 30

Pears in Container K	Pears in Container L	Pears in Container M	Total pears
1x2	5x2		6x2
2x1	5x1
2 u	5 u	5 u	12 u

40% = ⁴⁰₁₀₀ = ²₅

The number of pears in Container K is repeated.  Make the number of pears in Container K the same.  LCM of 1 and 2 is 2. 

Total number of pears
= 2 u + 5 u + 5 u
= 12 u

12 u = 36

1 u = 36 ÷ 12 = 3

Number of pears in Container M
= 5 u
= 5 x 3
= 15

Number of oranges in Container M
= 30 - 15
= 15

Percentage of the fruits in Container M are oranges
= ¹⁵₃₀ x 100%
= 50%

Answer(s): 50%